Implementing copy and assignment

• Expr::Expr(const Expr& e): p(e.p)
  {
  ++p->use;
  }

• Expr& Expr::operator=(const Expr& e)
  {
  ++e.p->use;
  if (--p->use == 0)
  delete p;
  p = e.p;
  return *this;
  }

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