/*--------------------------------------------------------------------*/ /* testalarmtimeout.c */ /* Author: Bob Dondero */ /*--------------------------------------------------------------------*/ #define _GNU_SOURCE #include #include #include #include #include /*--------------------------------------------------------------------*/ /* This function is intended to be a handler for signals of type SIGALRM. Write a timeout message to stdout, and exit. iSignal is number of the signal that caused this handler to execute. */ static void myHandler(int iSignal) { /* Really shouldn't call printf() or exit() here. See Bryant & O'Hallaron page 766. */ printf("\nSorry. You took too long.\n"); exit(EXIT_FAILURE); } /*--------------------------------------------------------------------*/ /* Demonstrate using an alarm to cause a timeout. As usual, argc is the command-line argument count, and argv contains the command-line arguments. Return 0. */ int main(int argc, char *argv[]) { enum {ALARM_DURATION_SECONDS = 5}; const char *pcPgmName; int i; void (*pfRet)(int); pcPgmName = argv[0]; /* Install myHandler as the handler for SIGALRM signals. */ pfRet = signal(SIGALRM, myHandler); if (pfRet == SIG_ERR) {perror(pcPgmName); exit(EXIT_FAILURE); } printf("Enter a number: "); alarm(ALARM_DURATION_SECONDS); scanf("%d", &i); alarm(0); printf("You entered the number %d.\n", i); return 0; } /*--------------------------------------------------------------------*/ /* Sample execution: $ gcc217 testalarmtimeout.c -o testalarmtimeout $ ./testalarmtimeout Enter a number: 123 You entered the number 123. $ ./testalarmtimeout Enter a number: Sorry. You took too long. */