public static String method1(int N)
    {
        String s = "";
        String x = "x";
        for (int i = 0; i < N; i++)
            s = s + x;
        return s;
    }
    public static String method2(int N)
    {
        String s = "";
        String x = "x";
	while (N != 0)
        {
	   if (N % 2 == 1) s = s + x;
           x = x + x;
           N = N/2;
        }
        return s;
    }
Hint: Recall that concatenating two strings in Java takes time
proportional to the sum of their lengths.
2. 
In this exercise, you will develop a quadratic-time algorithm for the 3-sum problem.
When we ask you to design an algorithm, give a crisp and concise
English description of your algorithm—don't write Java code.
Hint: start by checking whether a[0] + a[N-1] is smaller than, greater than, or equal to x.
Hint: Use the result from (a). You can assume the array is sorted since sorting the array can be done in quadratic (and even linearithmic) time.